arr+1 vs &arr+1

int arr[5] = {10,20,30,40,50};

Here,

arr is an integer pointer (int*) which points the first element of the array.

&arr is an integer array pointer (int*)[5] which points the whole array. (all five elements.)

&arr + 1 arr + 1

&arr is a pointer to an entire array. So, if we move &arr by 1 position it will point the next block of 5 elements.

arr is a pointer to the first element of the array.So, if we move arr by 1 position it will point the second element.

If the array base address is 1000, &arr+1 will be 1000 + (5 * 4) which is 1020

If the array base address is 1000, arr+1 will be 1000 + 4 which is 1004
arr+1 vs &arr+1

Example

#include<stdio.h>

int main()
{
    int arr[5] = {10, 20, 30, 40, 50};

    printf("arr = %p \t arr+1 = %p\n",arr,arr+1);
    printf("&arr = %p \t &arr+1 = %p\n",&arr,&arr+1);

    return 0;
}