Shell program to find average of n numbers

Let's write a shell program to find average of n numbers



Algorithm

1. Get N (Total Numbers)

2. Get N numbers using loop

3. Calculate sum

4. Average = sum / N

5. print the result.



Average of n numbers - Shell Script

#shell script to find average of n numbers

echo "Enter Size(N)"
read N

i=1
sum=0

echo "Enter Numbers"
while [ $i -le $N ]
do
  read num               #get number
  sum=$((sum + num))     #sum+=num
  i=$((i + 1))
done

avg=$(echo $sum / $N | bc -l)

echo $avg

We can't directly perform floating point arithmetic in bash.

So that we have used bc "An arbitrary precision calculator language" to calculate the avg.



Output

Enter Size(N)

5

Enter Numbers

10

20

30

40

50

30.00000000000000000000


Enter Size(N)

3

Enter Numbers

1

2

5

2.66666666666666666666



Use printf to print required floating points

#shell script to find average of n numbers

echo "Enter Size(N)"
read N

i=1
sum=0

echo "Enter Numbers"
while [ $i -le $N ]
do
  read num               #get number
  sum=$((sum + num))     #sum+=num
  i=$((i + 1))
done

avg=$(echo $sum / $N | bc -l)

printf '%0.2f' "$avg"

%0.2f will print only 2 floating numbers.



Output

Enter Size(N)

5

Enter Numbers

10

20

30

40

50

30.00


Enter Size(N)

3

Enter Numbers

1

2

5

2.67


Useful Resources

To learn more shell script examples, you can visit the link