Shell script to print sum of all digit

Let's write a shell script to print the sum of all digits in a given number.



Algorithm

1. Get a number

2. Split each digit from the number using modulo operator.

3. Calculate the sum

4. Print the result.



Sum of all digits - Shell Script

echo "Enter a number"
read num

sum=0

while [ $num -gt 0 ]
do
    mod=$((num % 10))    #It will split each digits
    sum=$((sum + mod))   #Add each digit to sum
    num=$((num / 10))    #divide num by 10.
done

echo $sum


Shell script to print sum of all digit using expr

#sum of all digits - shell script

echo "Enter a number"
read num

sum=0

while [ $num -gt 0 ]
do
    mod=`expr $num % 10`    #It will split each digits
    sum=`expr $sum + $mod`  #Add each digit to sum
    num=`expr $num / 10`    #divide num by 10.
done

echo $sum


Visual Representation

Split a number into digits

In our algorithm, we just added each digit to the sum.



Output

Enter a number

100

1


Enter a number

786

21


Useful Resources

To learn more shell script examples, you can visit the link